0=340x-x^2

Solution for 0=340x-x^2 equation:

0=340x-x^2

We move all terms to the left:

0-(340x-x^2)=0

We add all the numbers together, and all the variables

-(340x-x^2)=0

We get rid of parentheses

x^2-340x=0

a = 1; b = -340; c = 0;
Δ = b2-4ac
Δ = -3402-4·1·0
Δ = 115600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{115600}=340$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-340)-340}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-340)+340}{2*1}=\frac{680}{2}
=340
$